Last night, at the conclusion of AEW’s inaugural event, “Double or Nothing,” the wrestling world was stunned when Jon Moxley made his way through the crowd and attacked Chris Jericho, an official and Kenny Omega.
But when will be actually be wrestling for the promotion?
According to Justin Barrasso of Sports Illustrated, Moxley will make his in-ring debut on June 29 at Fyter Fest in Daytona Beach, Florida.
AEW confirms that Jon Moxley — formerly known as WWE's Dean Ambrose — has signed a multi-year deal and will made his in-ring debut on June 29 at Fyter Fest in Daytona Beach, Florida. #DoubleOrNothing pic.twitter.com/U5gMUpoxKH
— Justin Barrasso (@JustinBarrasso) May 26, 2019
You can see a clip of his debut below:
https://www.youtube.com/watch?v=1dwDqq17Onw
AEW President Tony Khan had the following to say regarding Moxley’s contract:
“He is a multi-year contract, he will be on a full-time deal,” Khan confirmed. “When we go weekly, he’s going to be full-time. Same as some of the guys, especially when the schedule is light, I’m open to him working some international and indie dates. He is full-time with us, domestically, essentially he’s our guy. Yeah, he’s going to do some international and indie stuff, but he’s definitely an AEW full-time wrestler.
“As soon as [Moxley] was out of his deal and wanted to talk to people, he came to me,” Khan said. “And I was really excited to talk to him when he was able to talk to me. He’s been great and I’m really excited he’s part of the roster.”
[h/t to Wrestling Inc.]
Moxley competed in WWE as Dean Ambrose from 2011-2019.
Editor’s Thoughts:
WWE should be scared. Really, really scared. AEW seems legit and is going to be real competition for them.
What do you think of Jon Moxley debuting with AEW? Leave us a comment below, or post a comment on our Facebook page! Also, be sure to sign up for our newsletter and download our App from your favorite App Store!